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55<H2><A NAME="SECTION0071620000000000000000"></A><A NAME="itertools-example"></A>
56<BR>
575.16.2 Examples
58</H2>
59
60<P>
61The following examples show common uses for each tool and
62demonstrate ways they can be combined.
63
64<P>
65<div class="verbatim"><pre>
66&gt;&gt;&gt; amounts = [120.15, 764.05, 823.14]
67&gt;&gt;&gt; for checknum, amount in izip(count(1200), amounts):
68... print 'Check %d is for $%.2f' % (checknum, amount)
69...
70Check 1200 is for $120.15
71Check 1201 is for $764.05
72Check 1202 is for $823.14
73
74&gt;&gt;&gt; import operator
75&gt;&gt;&gt; for cube in imap(operator.pow, xrange(1,5), repeat(3)):
76... print cube
77...
781
798
8027
8164
82
83&gt;&gt;&gt; reportlines = ['EuroPython', 'Roster', '', 'alex', '', 'laura',
84 '', 'martin', '', 'walter', '', 'mark']
85&gt;&gt;&gt; for name in islice(reportlines, 3, None, 2):
86... print name.title()
87...
88Alex
89Laura
90Martin
91Walter
92Mark
93
94# Show a dictionary sorted and grouped by value
95&gt;&gt;&gt; from operator import itemgetter
96&gt;&gt;&gt; d = dict(a=1, b=2, c=1, d=2, e=1, f=2, g=3)
97&gt;&gt;&gt; di = sorted(d.iteritems(), key=itemgetter(1))
98&gt;&gt;&gt; for k, g in groupby(di, key=itemgetter(1)):
99... print k, map(itemgetter(0), g)
100...
1011 ['a', 'c', 'e']
1022 ['b', 'd', 'f']
1033 ['g']
104
105# Find runs of consecutive numbers using groupby. The key to the solution
106# is differencing with a range so that consecutive numbers all appear in
107# same group.
108&gt;&gt;&gt; data = [ 1, 4,5,6, 10, 15,16,17,18, 22, 25,26,27,28]
109&gt;&gt;&gt; for k, g in groupby(enumerate(data), lambda (i,x):i-x):
110... print map(operator.itemgetter(1), g)
111...
112[1]
113[4, 5, 6]
114[10]
115[15, 16, 17, 18]
116[22]
117[25, 26, 27, 28]
118</pre></div>
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156<span class="release-info">Release 2.4.2, documentation updated on 28 September 2005.</span>
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