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Fix: Don't allow a separator as root for submenus.
author
Tobias R. Henle
<tobias@page23.de>
Mon, 5 Apr 2021 19:27:48 +0000
(21:27 +0200)
committer
Tobias R. Henle
<tobias@page23.de>
Mon, 5 Apr 2021 19:27:48 +0000
(21:27 +0200)
xmenu.c
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diff --git
a/xmenu.c
b/xmenu.c
index
afb4301
..
a4c29e1
100644
(file)
--- a/
xmenu.c
+++ b/
xmenu.c
@@
-432,6
+432,10
@@
buildmenutree(unsigned level, const char *label, const char *output, char *file)
for (item = prevmenu->list; item->next != NULL; item = item->next)
;
for (item = prevmenu->list; item->next != NULL; item = item->next)
;
+ /* a separator is no valid root for a submenu */
+ if (!item->label)
+ errx(1, "a separator is no valid root for a submenu");
+
prevmenu = menu;
menu->caller = item;
item->submenu = menu;
prevmenu = menu;
menu->caller = item;
item->submenu = menu;