set socket pgrp to avoid races; block SIGURG till done;
[unix-history] / usr / src / lib / libc / net / ns_addr.c
CommitLineData
2bbb9c02
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1/*
2 * Copyright (c) 1986 Regents of the University of California.
3 * All rights reserved. The Berkeley software License Agreement
4 * specifies the terms and conditions for redistribution.
5 *
6 * Includes material written at Cornell University, by J. Q. Johnson.
7 * Used by permission.
8 */
9
2ce81398
DS
10#if defined(LIBC_SCCS) && !defined(lint)
11static char sccsid[] = "@(#)ns_addr.c 6.2 (Berkeley) %G%";
12#endif LIBC_SCCS and not lint
2bbb9c02
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13
14#include <sys/types.h>
15#include <netns/ns.h>
16
17static struct ns_addr addr, zero_addr;
18
19struct ns_addr
20ns_addr(name)
21 char *name;
22{
23 u_long net;
24 u_short socket;
25 char separator = '.';
26 char *hostname, *socketname, *cp;
27 char buf[50];
28 extern char *index();
29
30 addr = zero_addr;
31 strncpy(buf, name, 49);
32
33 /*
34 * First, figure out what he intends as a field separtor.
35 * Despite the way this routine is written, the prefered
36 * form 2-272.AA001234H.01777, i.e. XDE standard.
37 * Great efforts are made to insure backward compatability.
38 */
39 if (hostname = index(buf, '#'))
40 separator = '#';
41 else {
42 hostname = index(buf, '.');
43 if ((cp = index(buf, ':')) &&
44 ( (hostname && cp < hostname) || (hostname == 0))) {
45 hostname = cp;
46 separator = ':';
47 }
48 }
49 if (hostname)
50 *hostname++ = 0;
51 Field(buf, addr.x_net.c_net, 4);
52 if (hostname == 0)
53 return (addr); /* No separator means net only */
54
55 socketname = index(hostname, separator);
56 if (socketname) {
57 *socketname++ = 0;
58 Field(socketname, &addr.x_port, 2);
59 }
60
61 Field(hostname, addr.x_host.c_host, 6);
62
63 return (addr);
64}
65
66static
67Field(buf, out, len)
68char *buf;
69u_char *out;
70int len;
71{
72 register char *bp = buf;
73 int i, ibase, base16 = 0, base10 = 0, clen = 0;
74 int hb[6], *hp;
75 char *fmt;
76
77 /*
78 * first try 2-273#2-852-151-014#socket
79 */
80 if ((*buf != '-') &&
81 (1 < (i = sscanf(buf, "%d-%d-%d-%d-%d",
82 &hb[0], &hb[1], &hb[2], &hb[3], &hb[4])))) {
83 cvtbase(1000, 256, hb, i, out, len);
84 return;
85 }
86 /*
87 * try form 8E1#0.0.AA.0.5E.E6#socket
88 */
89 if (1 < (i = sscanf(buf,"%x.%x.%x.%x.%x.%x",
90 &hb[0], &hb[1], &hb[2], &hb[3], &hb[4], &hb[5]))) {
91 cvtbase(256, 256, hb, i, out, len);
92 return;
93 }
94 /*
95 * try form 8E1#0:0:AA:0:5E:E6#socket
96 */
97 if (1 < (i = sscanf(buf,"%x:%x:%x:%x:%x:%x",
98 &hb[0], &hb[1], &hb[2], &hb[3], &hb[4], &hb[5]))) {
99 cvtbase(256, 256, hb, i, out, len);
100 return;
101 }
102 /*
103 * This is REALLY stretching it but there was a
104 * comma notation separting shorts -- definitely non standard
105 */
106 if (1 < (i = sscanf(buf,"%x,%x,%x",
107 &hb[0], &hb[1], &hb[2]))) {
108 hb[0] = htons(hb[0]); hb[1] = htons(hb[1]);
109 hb[2] = htons(hb[2]);
110 cvtbase(65536, 256, hb, i, out, len);
111 return;
112 }
113
114 /* Need to decide if base 10, 16 or 8 */
115 while (*bp) switch (*bp++) {
116
117 case '0': case '1': case '2': case '3': case '4': case '5':
118 case '6': case '7': case '-':
119 break;
120
121 case '8': case '9':
122 base10 = 1;
123 break;
124
125 case 'a': case 'b': case 'c': case 'd': case 'e': case 'f':
126 case 'A': case 'B': case 'C': case 'D': case 'E': case 'F':
127 base16 = 1;
128 break;
129
130 case 'x': case 'X':
131 *--bp = '0';
132 base16 = 1;
133 break;
134
135 case 'h': case 'H':
136 base16 = 1;
137 /* fall into */
138
139 default:
140 *--bp = 0; /* Ends Loop */
141 }
142 if (base16) {
143 fmt = "%3x";
144 ibase = 4096;
145 } else if (base10 == 0 && *buf == '0') {
146 fmt = "%3o";
147 ibase = 512;
148 } else {
149 fmt = "%3d";
150 ibase = 1000;
151 }
152
153 for (bp = buf; *bp++; ) clen++;
154 if (clen == 0) clen++;
155 if (clen > 18) clen = 18;
156 i = ((clen - 1) / 3) + 1;
157 bp = clen + buf - 3;
158 hp = hb + i - 1;
159
160 while (hp > hb) {
161 sscanf(bp, fmt, hp);
162 bp[0] = 0;
163 hp--;
164 bp -= 3;
165 }
166 sscanf(buf, fmt, hp);
167 cvtbase(ibase, 256, hb, i, out, len);
168}
169
170static
171cvtbase(oldbase,newbase,input,inlen,result,reslen)
172 int oldbase, newbase;
173 int input[];
174 int inlen;
175 unsigned char result[];
176 int reslen;
177{
178 int d, e;
179 long sum;
180
181 e = 1;
182 while (e > 0 && reslen > 0) {
183 d = 0; e = 0; sum = 0;
184 /* long division: input=input/newbase */
185 while (d < inlen) {
186 sum = sum*oldbase + (long) input[d];
187 e += (sum > 0);
188 input[d++] = sum / newbase;
189 sum %= newbase;
190 }
191 result[--reslen] = sum; /* accumulate remainder */
192 }
193 for (d=0; d < reslen; d++)
194 result[d] = 0;
195}