4.4BSD snapshot (revision 8.1)
[unix-history] / usr / src / usr.bin / w / proc_compare.c
/*-
* Copyright (c) 1990 The Regents of the University of California.
* All rights reserved.
*
* %sccs.include.redist.c%
*/
#ifndef lint
static char sccsid[] = "@(#)proc_compare.c 5.5 (Berkeley) %G%";
#endif /* not lint */
/*
* Returns 1 if p2 is more active than p1
*
* The algorithm for picking the "more active" process is thus:
*
* 1) Runnable processes are favored over anything
* else. The runner with the highest cpu
* utilization is picked (p_cpu). Ties are
* broken by picking the highest pid.
* 2) Next, the sleeper with the shortest sleep
* time is favored. With ties, we pick out
* just short-term sleepers (p_pri <= PZERO).
* Further ties are broken by picking the highest
* pid.
*
* NOTE - if you change this, be sure to consider making
* the change in the kernel too (^T in kern/tty.c).
*
* TODO - consider whether pctcpu should be used
*
*/
#include <sys/param.h>
#include <sys/time.h>
#include <sys/proc.h>
#include "extern.h"
#define isrun(p) (((p)->p_stat == SRUN) || ((p)->p_stat == SIDL))
#define TESTAB(a, b) ((a)<<1 | (b))
#define ONLYA 2
#define ONLYB 1
#define BOTH 3
int
proc_compare(p1, p2)
register struct proc *p1, *p2;
{
if (p1 == NULL)
return (1);
/*
* see if at least one of them is runnable
*/
switch (TESTAB(isrun(p1), isrun(p2))) {
case ONLYA:
return (0);
case ONLYB:
return (1);
case BOTH:
/*
* tie - favor one with highest recent cpu utilization
*/
if (p2->p_cpu > p1->p_cpu)
return (1);
if (p1->p_cpu > p2->p_cpu)
return (0);
return (p2->p_pid > p1->p_pid); /* tie - return highest pid */
}
/*
* weed out zombies
*/
switch (TESTAB(p1->p_stat == SZOMB, p2->p_stat == SZOMB)) {
case ONLYA:
return (1);
case ONLYB:
return (0);
case BOTH:
return (p2->p_pid > p1->p_pid); /* tie - return highest pid */
}
/*
* pick the one with the smallest sleep time
*/
if (p2->p_slptime > p1->p_slptime)
return (0);
if (p1->p_slptime > p2->p_slptime)
return (1);
/*
* favor one sleeping in a non-interruptible sleep
*/
if (p1->p_flag&SSINTR && (p2->p_flag&SSINTR) == 0)
return (1);
if (p2->p_flag&SSINTR && (p1->p_flag&SSINTR) == 0)
return (0);
return(p2->p_pid > p1->p_pid); /* tie - return highest pid */
}