BSD 4_3_Net_1 release
[unix-history] / lib / libc / ns / ns_addr.c
/*
* Copyright (c) 1986 Regents of the University of California.
* All rights reserved.
*
* Redistribution and use in source and binary forms are permitted
* provided that the above copyright notice and this paragraph are
* duplicated in all such forms and that any documentation,
* advertising materials, and other materials related to such
* distribution and use acknowledge that the software was developed
* by the University of California, Berkeley. The name of the
* University may not be used to endorse or promote products derived
* from this software without specific prior written permission.
* THIS SOFTWARE IS PROVIDED ``AS IS'' AND WITHOUT ANY EXPRESS OR
* IMPLIED WARRANTIES, INCLUDING, WITHOUT LIMITATION, THE IMPLIED
* WARRANTIES OF MERCHANTIBILITY AND FITNESS FOR A PARTICULAR PURPOSE.
*
* This code is derived from software contributed to Berkeley by
* J.Q. Johnson at Cornell University.
*/
#if defined(LIBC_SCCS) && !defined(lint)
static char sccsid[] = "@(#)ns_addr.c 6.4 (Berkeley) 8/12/88";
#endif /* LIBC_SCCS and not lint */
#include <sys/types.h>
#include <netns/ns.h>
static struct ns_addr addr, zero_addr;
struct ns_addr
ns_addr(name)
char *name;
{
char separator = '.';
char *hostname, *socketname, *cp;
char buf[50];
extern char *index();
addr = zero_addr;
(void)strncpy(buf, name, 49);
/*
* First, figure out what he intends as a field separtor.
* Despite the way this routine is written, the prefered
* form 2-272.AA001234H.01777, i.e. XDE standard.
* Great efforts are made to insure backward compatability.
*/
if (hostname = index(buf, '#'))
separator = '#';
else {
hostname = index(buf, '.');
if ((cp = index(buf, ':')) &&
( (hostname && cp < hostname) || (hostname == 0))) {
hostname = cp;
separator = ':';
}
}
if (hostname)
*hostname++ = 0;
Field(buf, addr.x_net.c_net, 4);
if (hostname == 0)
return (addr); /* No separator means net only */
socketname = index(hostname, separator);
if (socketname) {
*socketname++ = 0;
Field(socketname, (u_char *)&addr.x_port, 2);
}
Field(hostname, addr.x_host.c_host, 6);
return (addr);
}
static
Field(buf, out, len)
char *buf;
u_char *out;
int len;
{
register char *bp = buf;
int i, ibase, base16 = 0, base10 = 0, clen = 0;
int hb[6], *hp;
char *fmt;
/*
* first try 2-273#2-852-151-014#socket
*/
if ((*buf != '-') &&
(1 < (i = sscanf(buf, "%d-%d-%d-%d-%d",
&hb[0], &hb[1], &hb[2], &hb[3], &hb[4])))) {
cvtbase(1000L, 256, hb, i, out, len);
return;
}
/*
* try form 8E1#0.0.AA.0.5E.E6#socket
*/
if (1 < (i = sscanf(buf,"%x.%x.%x.%x.%x.%x",
&hb[0], &hb[1], &hb[2], &hb[3], &hb[4], &hb[5]))) {
cvtbase(256L, 256, hb, i, out, len);
return;
}
/*
* try form 8E1#0:0:AA:0:5E:E6#socket
*/
if (1 < (i = sscanf(buf,"%x:%x:%x:%x:%x:%x",
&hb[0], &hb[1], &hb[2], &hb[3], &hb[4], &hb[5]))) {
cvtbase(256L, 256, hb, i, out, len);
return;
}
/*
* This is REALLY stretching it but there was a
* comma notation separting shorts -- definitely non standard
*/
if (1 < (i = sscanf(buf,"%x,%x,%x",
&hb[0], &hb[1], &hb[2]))) {
hb[0] = htons(hb[0]); hb[1] = htons(hb[1]);
hb[2] = htons(hb[2]);
cvtbase(65536L, 256, hb, i, out, len);
return;
}
/* Need to decide if base 10, 16 or 8 */
while (*bp) switch (*bp++) {
case '0': case '1': case '2': case '3': case '4': case '5':
case '6': case '7': case '-':
break;
case '8': case '9':
base10 = 1;
break;
case 'a': case 'b': case 'c': case 'd': case 'e': case 'f':
case 'A': case 'B': case 'C': case 'D': case 'E': case 'F':
base16 = 1;
break;
case 'x': case 'X':
*--bp = '0';
base16 = 1;
break;
case 'h': case 'H':
base16 = 1;
/* fall into */
default:
*--bp = 0; /* Ends Loop */
}
if (base16) {
fmt = "%3x";
ibase = 4096;
} else if (base10 == 0 && *buf == '0') {
fmt = "%3o";
ibase = 512;
} else {
fmt = "%3d";
ibase = 1000;
}
for (bp = buf; *bp++; ) clen++;
if (clen == 0) clen++;
if (clen > 18) clen = 18;
i = ((clen - 1) / 3) + 1;
bp = clen + buf - 3;
hp = hb + i - 1;
while (hp > hb) {
(void)sscanf(bp, fmt, hp);
bp[0] = 0;
hp--;
bp -= 3;
}
(void)sscanf(buf, fmt, hp);
cvtbase((long)ibase, 256, hb, i, out, len);
}
static
cvtbase(oldbase,newbase,input,inlen,result,reslen)
long oldbase;
int newbase;
int input[];
int inlen;
unsigned char result[];
int reslen;
{
int d, e;
long sum;
e = 1;
while (e > 0 && reslen > 0) {
d = 0; e = 0; sum = 0;
/* long division: input=input/newbase */
while (d < inlen) {
sum = sum*oldbase + (long) input[d];
e += (sum > 0);
input[d++] = sum / newbase;
sum %= newbase;
}
result[--reslen] = sum; /* accumulate remainder */
}
for (d=0; d < reslen; d++)
result[d] = 0;
}